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Question

A piece of wire with resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R′, then the ratio RR′ is:

A

(1/25)

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B

(1/5)

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C

5

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D

25

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Solution

Step 1: Given data:

Resistance of a wire = R

The wire is divided in 5 equal parts, that is the resistance of each part is the same.

The equivalent resistance of the wire = R

Step 2: Formula used

The equivalent resistance of the combination of resistances connected in parallel is given by;

1Req=1R1+1R2+1R3+..............+1Rn

Step 3: Finding the equivalent resistance

Let, the new resistance of each one of the five parts be Rn then,

Rn=R5

Therefore

Resistance of five parts connected in parallel is given by

1Req=1Rn+1Rn+1Rn+1Rn+1Rn

1R=5R+5R+5R+5R+5R

1R=5×5R

1R=25R

R=R25

Step 4: Finding the ratio of R and R'

R=R25

RR=125

RR=251

Hence,

option D) RR=25 is the correct option.


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