A piece of wire with resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R′, then the ratio RR′ is:
Step 1: Given data:
Resistance of a wire = R
The wire is divided in 5 equal parts, that is the resistance of each part is the same.
The equivalent resistance of the wire = R′
Step 2: Formula used
The equivalent resistance of the combination of resistances connected in parallel is given by;
1Req=1R1+1R2+1R3+..............+1Rn
Step 3: Finding the equivalent resistance
Let, the new resistance of each one of the five parts be Rn then,
Rn=R5
Therefore
Resistance of five parts connected in parallel is given by
1Req=1Rn+1Rn+1Rn+1Rn+1Rn
1R′=5R+5R+5R+5R+5R
1R′=5×5R
1R′=25R
R′=R25
Step 4: Finding the ratio of R and R'
R′=R25
R′R=125
RR′=251
Hence,
option D) RR′=25 is the correct option.