A piece of wood has a mass 2 kg and dimensions 1 m - 2 m - 3 m- Density of the wooden block is- A- 3 - 10-3 kgm 3B- 0-33 kgm 3C- 0-33 - 10-3 kgm 3

The correct option is B 0.33 nbsp;kgm3Given, nbsp; Mass of the block = 2 kg Volume of the block = nbsp;1 m×2 m×3 m = 6 m^3 Density = Mass/Volume Densit ...

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Standard IX

Physics

Archimedes' Principle

A piece of wo...

Question

A piece of wood has a mass $2 k g$ and dimensions $1 m \times 2 m \times 3 m$ . Density of the wooden block is .

3 \times 10^{- 3} \frac{k g}{m^{3}}

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0.33 \frac{k g}{m^{3}}

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0.33 \times 10^{- 3} \frac{k g}{m^{3}}

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Solution

The correct option is B $0.33 \frac{k g}{m^{3}}$
Given,
Mass of the block = $2 k g$
Volume of the block = $1 m \times 2 m \times 3 m$ = $6 m^{3}$
Density = $\frac{M a s s}{V o l u m e}$
Density of the block = $\frac{2 k g}{6 m^{3}}$ = $0.33 k g / m^{3}$

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A piece of wood has a mass 2 kg and dimensions 1 m×2 m×3 m. Density of the wooden block is .

The correct option is B 0.33 kg/m3Given, Mass of the block = 2 kg Volume of the block = 1 m×2 m×3 m = 6 m3 Density = MassVolume Density of the block = 2 kg6 m3 = 0.33 kg/m3

A piece of wood has a mass $2 k g$ and dimensions $1 m \times 2 m \times 3 m$ . Density of the wooden block is .

The correct option is B $0.33 \frac{k g}{m^{3}}$
Given,
Mass of the block = $2 k g$
Volume of the block = $1 m \times 2 m \times 3 m$ = $6 m^{3}$
Density = $\frac{M a s s}{V o l u m e}$
Density of the block = $\frac{2 k g}{6 m^{3}}$ = $0.33 k g / m^{3}$