A piece of wood having dimensions $1 m \times 2 m \times 3 m$ and $2 k g$ mass. What is the density of wood? Would the wood float in water? ( $d_{w a t e r} = 1000 k g / m^{3}$ )

0.33, YES

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0.33 x 10^-3,NO

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3,YES

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3 x 10^-3, NO

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Solution

The correct option is B
0.33 x 10^-3,NO

Volume of the wood = $1 m \times 2 m \times 3 m$ = $6 m^{3}$ .
So, the density of wood = $\frac{m a s s o f w o o d}{v o l u m e o f w o o d}$ .
Hence, $d_{w o o d}$ = $\frac{2 k g}{6 m^{3}}$ = $0.33 k g / m^{3}$ .
Now, to check whether the wood floats or not we need to calculate the relative density with respect to water as a reference material (or specific gravity).
So, specific gravity = $\frac{0.33}{1000}$ = $0.33 \times 10^{-} 3$ which is less than $1$ .
Hence, the substance is less dense than water and it would float.

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A piece of wood having dimensions 1 m×2 m×3 m and 2 kg mass. What is the density of wood? Would the wood float in water? (dwater = 1000 kg/m3)

A piece of wood having dimensions $1 m \times 2 m \times 3 m$ and $2 k g$ mass. What is the density of wood? Would the wood float in water? ( $d_{w a t e r} = 1000 k g / m^{3}$ )