A piece of wood is $3 m$ long, $2 m$ wide and has a thickness of $1 m$ . Find the density of wood if its mass is $2 k g$ .

$0.03 k g m^{- 3}$

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$33 k g m^{- 3}$

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$0.33 k g m^{- 3}$

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$3.33 k g m^{- 3}$

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Solution

The correct option is C
$0.33 k g m^{- 3}$

Given: Mass of piece of wood, M = $2 k g$
Volume of piece of wood, $V$ = $1 m \times 2 m \times 3 m = 6 m^{3}$

$D e n s i t y o f w o o d = \frac{Mass of wood}{Volume of wood}$
Hence, $d_{wood} = \frac{2 k g}{6 m^{3}}$ = $0.33 k g m^{- 3}$

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