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Question

A piece of wood of mass 6 kg is floating in water with its 13rd part inside the water. On this floating piece of wood, what maximum mass can be put such that the whole of the piece of wood gets drowned in the water?

A
15 kg
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B
14 kg
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C
10 kg
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D
12 kg
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Solution

The correct option is D 12 kg
Weight of the submerged part of the block,
W=13Vρwg ..........(i)
where ρw is density of water.
Now,
Excess weight(W) = weight of water having 23rd volume of the block.
W=23Vρwg ........(ii)
Dividing (ii) by (i), WW=2313
W=2WW=2×6=12 kg

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