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Question

A piece of wood of relative density 0.25 floats in a pot containing oil of relative density 0.81. What will be the fraction of volume of the wood above the surface of the oil. (density of water = 1000 kg/m3)

A

0.31

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B

0.81

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C

0.69

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D

data insufficient

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Solution

The correct option is C

0.69


If V1 is the volume of the wood in oil and V2 is the volume of the wood in air, then,

V1ρ1g=V2ρ2g

Where ρ1 and ρ2 are the relative densities of oil and wood respectively

V1V2 = 0.250.81 = 0.31

Fraction of the volume above the surface of oil = 1V1V2 = 0.69


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