CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A piece of zinc at a temperature of 20oC weighing 65.38 g is dropped into 180 g of boiling water (T=100oC). The specific heat of zinc is 0.4 J g1 C1 and that of water is 4.2 J g1 oC1. What is the final common temperature reached by both the zinc and water? 
  1. 97.3 oC
  2. 33.4 oC
  3. 80.1 oC
  4. 60.0 oC


Solution

The correct option is A 97.3 oC
Let final common temperature is Tf
According to law of energy conservation :
Heat gained by Zinc piece = Heat lost by water 
mZn sT=mH2O sT, where, s is specific heat capacity.
65.38×0.4(Tf293)=180×4.2(373Tf)
=Tf293373Tf=28.90
=29.90Tf=28.90×373+293
Tf=370.32 K
Hence, final common temperature reached by both the zinc and water (Tf)=97.3oC

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image