Question

A piece of zinc foil was dipped into a beaker containing copper sulphte solution.The reactants were left for an hour to allow them to react.
(a) Write a balanced chemical equation to represent this reaction.
(b)What is this reactions called? Define the reaction.
(c)What would you observed if a piece of silver metal was dipped into the copper sulphate solution instead of zinc ? Give reason for your answer.

Answer 1

(a)

When zinc & oil is dipped in $CuS{O}_4$ solutoin these redox reaction occurs, since zine is more reaction then copper thus displaces $cu$ from $CuS{O}_4$ solution

Balanced Chemical reaction

$Z{n}_{\left(s\right)}+CuS{O}_{4\left(aq\right)}⟶ZnS{O}_{4\left(aq\right)}+C{u}_{\left(s\right)}$
(b)

The reaction is called as displacement reaction Displacement Reaction = Displacement reaction is a chemical reaction basically in which a more reactive metal ( from reactivity series) displaces a less reactive metals.

Other Examples: $F{e}_{\left(s\right)}+CuS{O}_{4\left(aq\right)}⟶FeS{O}_{4\left(aq\right)}+C{u}_{\left(s\right)}$

(c)

No reaction will takes place when silver metal;s is dipped into copper sulphate solution instead of $Zn$.

$A{g}^{+}+CuS{O}_4⟶$ No reaction

Reason: It is because silver $\left(Aq\right)$ has less reactivity than $Cu$, due to which it cannot displaces $\left(C{u}^{2+}\right)$ ion from its compounds $CuS{O}_4$