A piggy bank contains hundred 50 p coins, fifty Re. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will be a 50 p coin?

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Solution

Total number of coins in a piggy bank = 100+50+20+10 = 180
$∴$ Total number of elementary events = 180
There are one hundred 50 coins in the piggy bank.
$∴$ Favourable number of elementary events = 100
$∴$ P (falling out of 50 p coin) = $\frac{100}{180} = \frac{5}{9}$

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A piggy bank contains hundred 50 p coins, fifty Re. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will be a 50 p coin?

Total number of coins in a piggy bank = 100+50+20+10 = 180 ∴ Total number of elementary events = 180 There are one hundred 50 coins in the piggy bank. ∴ Favourable number of elementary events = 100 ∴ P (falling out of 50 p coin) = 100180=59

Total number of coins in a piggy bank = 100+50+20+10 = 180
$∴$ Total number of elementary events = 180
There are one hundred 50 coins in the piggy bank.
$∴$ Favourable number of elementary events = 100
$∴$ P (falling out of 50 p coin) = $\frac{100}{180} = \frac{5}{9}$