Question

A: pilot of mass $m$ can withstand a maximum apparent weight $6$ times of $mg$. The minimum radius of curvature of vertical circle in which the aeroplane dives up from lowest point with a speed $504kmph$ is:

• A. $200m$
• B. $300m$
• C. $400m$
• D. $500m$

Answer 1

Answer: (C)

$400m$

$V=504Km/h$
$=504\times \frac{5}{18}=140m/s$
If pilot can withstand apparent weight of 6 times of $mg$ then, max centripetal acceleration should be equal to $mg$ at bottom most point.
$\frac{m{v}^2}{R}=6mg$

$\frac{(140{)}^2}{6\times 10}=R=326m$

Radius should be greater than $326m$.

Here, minimum safe radius is $400m$