A pilot of mass 75 kg in a jet aircraft executes a loop with a constant speed of 360 km/hr. If the radius of the loop is 200 m, the force exerted by seat on the pilot at the top of the loop is (Takeg=10m/s2)
A
3750N
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B
4485N
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C
3000N
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D
5843N
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Solution
The correct option is C3000N At the top most point, FBD of pilot:-
Here Nps is the normal on pilot by the seat in the downward direction v=360km/h=360×518 ⇒v=100m/s Applying Equation of dynamics :- Net force on the pilot by the seat N=mv2R−mg