Question

# A pilot of mass 75 kg in a jet aircraft executes a loop with a constant speed of 360 km/hr. If the radius of the loop is 200 m, the force exerted by seat on the pilot at the top of the loop is (Take g=10 m/s2)

A
3750 N
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B
4485 N
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C
3000 N
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D
5843 N
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Solution

## The correct option is C 3000 NAt the top most point, FBD of pilot:- Here Nps is the normal on pilot by the seat in the downward direction v=360 km/h =360×518 ⇒v=100 m/s Applying Equation of dynamics :- Net force on the pilot by the seat N=mv2R−mg =75×(100)2200−75×10 ⇒Required net force =(3750−750)N =3000 N Hence option C is the correct answer

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