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Question

A pin jointed 2D truss is loaded with a vertical force of 40 kN at joint F and another 40 kN horizontal magnitude force at joint B as shown in figure.

The force (in kN) in member BC is

A
0
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B
20
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C
None of these
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D
202
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Solution

The correct option is A 0
MA=0

RG×10=40×540×5

RG=0

From method of section

RA=40 kN

Taking moment about F,

40×540×5+FBC×5=0

FBC=0

Alternatively,

by inspection RG=0 [BME=0]

Force in member EG=0

Forces in member ED and CD is already zero.

Forces in member ED and EC is zero.

Similarly, forces in members BC and CF are zero.

Also, force in member AF=0

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