The correct option is B 5
Let number of pipe is represented by P and the capacity of tank is T.
As both the tanks need to be filled in 2 hours, when capacity of the tank will be more, more pipes will be required to fill it in a given time
Hence, P∝T
⇒P=k×T ∵k is a constant
⇒1=k×100 liter
⇒k=1100
⇒PT=1100
We have to find the number of pipe required to fill a tank of 500 l.
⇒PT=k⇒P=T×k (Multiply by T on both the sides)
Put the values of T and k.
T=500 liters, k=1100
⇒P=1100×500=5
Hence, 5 pipes are required.