A pipe closed at one end has length 83 cm. The number of possible natural oscillations of air column whose frequencies lie below 100Hz are (velocity of sound in air = 332 m/s)
A
0
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B
4
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C
5
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D
6
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Solution
The correct option is A0 We know that for a pipe closed at one end, a frequency is given by:-
f=n×v4L
v= speed of sound=332m/s
L=length of pipe=83cm=0.83m
n=0,1,2...
f=1×3324×0.83
⟹f=100Hz
Hence, no natural oscillation of frequency less than 100Hz.