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Question

A piston-cylinder device initially contains 0.4m3 of air (to be treated as an ideal gas) at 100 kPa and 80oC. The air is now isothermally compressed to 0.1m3. The work done during this process is kJ.
(Take the sign convention such that work done on the system is negative)
  1. -55.45

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Solution

The correct option is A -55.45
V1=0.4m3; p1=100kPa
T1=80oC=(80+273)K=353K
V2=0.1m3
For isothermal process

W=p1V1logeV2V1
=100×0.4loge0.10.4
=55.45kJ

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