CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A piston filled with 0.04 moles of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0 oC. As it does so, it absorbs 208 J of heat. What will be the value of q and W respectively ?

A
+208,+208
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
208,208
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
+208,208
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
208,+208
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C +208,208
Number of moles =0.04 mol
Initial volume =50.0 mL
Final volume =375 mL
Temperature =Constant (37.0 oC)
Heat absorbed=+208 J

We know that inernal energy is a function of temperature and here, the temperature is constant.
Hence, there is no change in the internal energy.
dU=0
The first law of thermodynamics is given as ;
ΔU=q+W
0=208 J+W
W=208 J

flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon