A pit 5 m long and 3.5 m wide is dug to a certain depth. If the volume of earth taken out of it is $14 m^{3}$ , what is the depth of the pit?

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Solution

Length of pit (l)=5m

Width (b)=3.5 m

Let depth of pit =h

then volume of earth dug out

$= l . b . h = 5 \times 3.5 \times h = 17.5 h m^{3}$

But volume of earth $= 14 m^{3}$

$∴ 17.5 h = 14$

$\Rightarrow h = \frac{14}{17.5} = \frac{140}{175}$

$\Rightarrow h = \frac{4}{5} m = \frac{4}{5} \times 100 = 80 c m$

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A pit 5 m long and 3.5 m wide is dug to a certain depth. If the volume of earth taken out of it is 14m3, what is the depth of the pit?

Length of pit (l)=5m Width (b)=3.5 m Let depth of pit =h then volume of earth dug out =l.b.h=5×3.5×h=17.5hm3 But volume of earth =14m3 ∴17.5h=14 ⇒h=1417.5=140175 ⇒h=45m=45×100=80cm

A pit 5 m long and 3.5 m wide is dug to a certain depth. If the volume of earth taken out of it is $14 m^{3}$ , what is the depth of the pit?