A plain sedimentation tank with a length of 20 m- width of 10 m- and a depth of 3 m is used in a water treatment plant to treat 4 million litre of water per day 4 MLD- The average temperature of water is 20-C - The dynamic viscosity of water is 1-002 - 10-3 Ns-m2 at 20- C- Density of water is 998-2 kg-m3- Average specific gravity of particles is 2-65What is the surface overflow rate in the sedimentation tank -

Surface overflow rate = QPlan area = 4MLD20 × 10 = 4 × 10^3 m^3/day200 m^2 = 20 m^3/m^2/day ...

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Pressure Due to Liquid Column

A plain sedim...

Question

A plain sedimentation tank with a length of $20 m$ , width of $10 m$ , and a depth of $3 m$ is used in a water treatment plant to treat 4 million litre of water per day (4 MLD). The average temperature of water is $20^{\circ} C$ . The dynamic viscosity of water is $1.002 \times 10^{- 3} N s / m^{2}$ at $20^{\circ} C$ . Density of water is $998.2 k g / m^{3}$ . Average specific gravity of particles is $2.65$
What is the surface overflow rate in the sedimentation tank ?

133 m^{3} / m^{2} / d a y

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40 m^{3} / m^{2} / d a y

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63 m^{3} / m^{2} / d a y

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20 m^{3} / m^{2} / d a y

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20 m

10 m

3 m

20^{\circ} C

1.002 \times 10^{- 3} N s / m^{2}

20^{\circ} C

k g / m^{3}

2.65

30 m^{3} / d a y . m^{2}

= 2.65

1000 k g / m^{3}

(μ) = 0.001 N . s / m^{2}

20 m \times 10 m \times 3 m

10^{- 2} c m^{2} / s e c

20^{\circ}

40 m^{3} / m^{2} / d

90

= 1000 k g / m^{3}

2650 K g / m^{3}

g = 9.81 m / s^{2}

(v) = 1.10 \times 10^{- 6} m^{2} / s

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