A plane area of $100 {c m}^{2}$ is placed in uniform electric field of $100 N / C$ such that the angle between area vector and electric field is $60^{o}$ . The electric flux over the surface is

0.5 Wb

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5 Wb

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1 Wb

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Solution

The correct option is A 0.5 Wb
Electric Flux $(ϕ) = \to E . \to A = E A cos θ$
$\Rightarrow ϕ = 0.01 m^{2} \times 100 N / C \times cos 60^{0}$
$\Rightarrow ϕ = 0.5 W b$

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A plane area of 100 cm2 is placed in uniform electric field of 100 N/C such that the angle between area vector and electric field is 60o. The electric flux over the surface is

The correct option is A 0.5 WbElectric Flux (ϕ)=→E.→A=EAcosθ⇒ϕ=0.01m2×100N/C×cos600⇒ϕ=0.5Wb

A plane area of $100 {c m}^{2}$ is placed in uniform electric field of $100 N / C$ such that the angle between area vector and electric field is $60^{o}$ . The electric flux over the surface is

The correct option is A 0.5 Wb
Electric Flux $(ϕ) = \to E . \to A = E A cos θ$
$\Rightarrow ϕ = 0.01 m^{2} \times 100 N / C \times cos 60^{0}$
$\Rightarrow ϕ = 0.5 W b$