A plane convex lens of focal length 16 cm, is to be made of glass of refractive index 1.5. The radius of curvature of the curved surface should be :

8 cm

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12 cm

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16 cm

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24 cm

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Solution

The correct option is A 8 cm
$\frac{1}{f} = (μ - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{16} = (1.5 - 1) [\frac{1}{R} - \frac{1}{\infty}]$

$\Rightarrow \frac{1}{16} = 0.5 \times \frac{1}{R} \Rightarrow R = 8 c m$

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A plane convex lens of focal length 16 cm, is to be made of glass of refractive index 1.5. The radius of curvature of the curved surface should be :

The correct option is A 8 cm1f=(μ−1)[1R1−1R2]116=(1.5−1)[1R−1∞]⇒116=0.5×1R⇒R=8cm

The correct option is A 8 cm
$\frac{1}{f} = (μ - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{16} = (1.5 - 1) [\frac{1}{R} - \frac{1}{\infty}]$

$\Rightarrow \frac{1}{16} = 0.5 \times \frac{1}{R} \Rightarrow R = 8 c m$