A plane flies 10 km east from city A to city B in 2 hrs and then 20 km south from city B to city C in 1 hr. For the total trip, what are the magnitude and direction of its average acceleration?

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Solution

The correct options are
A

D

Average acceleration $= \frac{{\to v}_{2} - {\to v}_{1}}{t}$

$_{1} = \frac{10}{2}^i = 5^i$ (East direction)

$_{2} = \frac{20}{1} (^- j) = - 20^j$ (south direction)

$∴ {\to a}_{a v g} = \frac{- 20^j - 5^i}{3}$ (time of flight=3hrs)

$= \frac{- 20}{3}^j - \frac{5}{3}^i$

since, both x component and y component are negative, it is in the south west direction.

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A plane flies 10 km east from city A to city B in 2 hrs and then 20 km south from city B to city C in 1 hr. For the total trip, what are the magnitude and direction of its average acceleration?

The correct options are A D Average acceleration =→v2−→v1t →v1=102^i=5^i (East direction) →v2=201(^−j)=−20^j (south direction) ∴→aavg=−20^j−5^i3(time of flight=3hrs) =−203^j−53^i since, both x component and y component are negative, it is in the south west direction.