A plane has a takeoff speed of $88.3 m / s$ and requires $1365 m$ to reach that speed. Determine the acceleration of the plane.

3.86 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.86 m / s^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.8 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.6 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $2.86 m / s^{2}$
Given, initial velocity is $u = 0 m / s$
Final velocity is $v = 88.3 m / s$ and traveled distance, $d = 1365 m$
Let $a$ be the acceleration of the plane.
Using $v^{2} - u^{2} = 2 a d$
$∴$ $(88.3)^{2} - 0^{2} = 2 a (1365)$
$⟹$ $a = 2.86 m / s^{2}$

Suggest Corrections

Similar questions

Q. A plane has a takeoff speed of

88.3 m / s

and requires

1365 m

to reach that speed. Determine the time required to reach this speed.

Q. A plane has take off speed of 88.1m/s and requires 1365m to reach that speed . Determine the acceleration of the plane and the time required to reach this speed.

A plane has a take-off speed of $120 \frac{m}{s}$ and it reaches that speed after covering 2400 m. Determine the acceleration of the plane (assuming it to be constant) and the time required to reach this speed?

Q. A plane starting at rest at one end of a runway undergoes a uniform acceleration of

4.8 m / s^{2}

for

15 s

before take-off. What is its speed of takeoff?

Q. An airliner reaches its takeoff speed of

163 m p h

36.2 s

. What is the magnitude of its average acceleration. (in

m / s^{2}

)

Join BYJU'S Learning Program

A plane has a takeoff speed of 88.3m/s and requires 1365m to reach that speed. Determine the acceleration of the plane.

The correct option is D 2.86m/s2Given, initial velocity is u=0m/sFinal velocity is v=88.3m/s and traveled distance, d=1365mLet a be the acceleration of the plane.Using v2−u2=2ad∴ (88.3)2−02=2a(1365)⟹ a=2.86m/s2

A plane has a takeoff speed of $88.3 m / s$ and requires $1365 m$ to reach that speed. Determine the acceleration of the plane.

The correct option is D $2.86 m / s^{2}$
Given, initial velocity is $u = 0 m / s$
Final velocity is $v = 88.3 m / s$ and traveled distance, $d = 1365 m$
Let $a$ be the acceleration of the plane.
Using $v^{2} - u^{2} = 2 a d$
$∴$ $(88.3)^{2} - 0^{2} = 2 a (1365)$
$⟹$ $a = 2.86 m / s^{2}$