Question

A plane is flying horizontally at $98$ $m{s}^{-1}$ and releases an object which reaches the ground in $10s$. The angle made by it while hitting the ground is:

• A. $55$
• B. $45$
• C. $60$
• D. $75$

Answer 1

The correct option is B $45$

Horizontal velocity of object is same as plane i.e., $98m/s$
Vertical velocity $=0+g\times t=9.8\times 10=98m/s$
The angle made by it while hitting the groud $=ta{n}^{-1}\frac{98}{98}=ta{n}^{-1}1={45}^o$