A plane is inclined 30o with horizontal. A block is placed on the plane at rest. Assume the coefficient of static friction between block and the plane is .5. The block will:
A
accelerate down the plane
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
accelerate briefly down the plane but then slow down and stop
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
move with constant velocity down the plane
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
not move
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
cannot be determined from the information given
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A accelerate down the plane Force acting on block down the plane=mgsinθ=mgsin30∘=mg2
Maximum static friction that can act on the plane=μN=μmgcosθ=0.5×mgcos30∘=√3mg4<mgsinθ
Thus the block would continue to accelerate down with magnitude=mg2−√3mg4m