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Question

A plane is inclined at an angle α=30 with respect to the horizontal. A particle is projected with a speed u=2 m/s, from the base of the plane, as shown in figure. The distance from the base, at which the particle hits the plane, is close to:
(Take g=10 m/s2)


A
20 cm
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B
180 cm
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C
26 cm
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D
14 cm
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Solution

The correct option is A 20 cm
On an inclined plane, time of flight (T) is given by,

T=2usinθgcosα

Substituting the values, we get

T=(2)(2sin15)gcos30=4sin1510cos30

Distance, S=(2cos15)T12gsin30(T)2


=(2cos15)410sin1510cos30(12×10sin30)16sin215100cos230

[sin150=3122]

=16316600.1952 m20 cm

Hence, (A) is the correct answer.

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