A plane lamina has an area 2m2 at 10-C then what is its area at 110-C- It-s co-efficient of superficial expansion is 2-10-5-C-

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Intensity Amplitude Relationship

A plane lamin...

Question

A plane lamina has an area $2 m^{2}$ at $10^{\circ} C$ then what is its area at $110^{\circ} C$ ? It's co-efficient of superficial expansion is $2 \times 10^{- 5} / C$ .

2.002 m^{2}

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2.004 m^{2}

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2.02 m^{2}

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2.04 m^{2}

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Solution

The correct option is A $2.004 m^{2}$
Let A be the final area and and $A_{o}$ be initial area
now $\frac{δ A}{A_{0}} = β δ T$
$\frac{δ A}{2} = 2 \times 10^{- 5} \times (110 - 10)$
$\frac{δ A}{2} = 2 \times 10^{- 3}$
$A - A_{0} = 2 \times 2 \times 10^{- 3}$
$A = 2.004 m^{3}$

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A plane lamina has an area 2m2 at 10∘C then what is its area at 110∘C? It's co-efficient of superficial expansion is 2×10−5/C.

The correct option is A 2.004m2Let A be the final area and and Ao be initial areanow δAA0=βδTδA2=2×10−5×(110−10)δA2=2×10−3A−A0=2×2×10−3A=2.004m3

A plane lamina has an area $2 m^{2}$ at $10^{\circ} C$ then what is its area at $110^{\circ} C$ ? It's co-efficient of superficial expansion is $2 \times 10^{- 5} / C$ .

The correct option is A $2.004 m^{2}$
Let A be the final area and and $A_{o}$ be initial area
now $\frac{δ A}{A_{0}} = β δ T$
$\frac{δ A}{2} = 2 \times 10^{- 5} \times (110 - 10)$
$\frac{δ A}{2} = 2 \times 10^{- 3}$
$A - A_{0} = 2 \times 2 \times 10^{- 3}$
$A = 2.004 m^{3}$