A plane left 30 minutes later than the scheduled time. In order to reach the destination 1500 km away in time, it has to increase the speed by 250 km/hr from the usual speed. Find its usual speed.
and the increased speed of the plane be y km/hr.
⇒ y=(x+250) km/hr
Distance =1500 km [Given]
According to the question,
(Scheduled time) - (time taken at increased speed) = 30 minutes = 0.5 hours.
1500x−1500y=12
1500x−1500x+250=12 [∵Time=DistanceSpeed]
⇒1500x+375000−1500xx(x+250)=12
⇒ x(x+250)=750000
⇒ x2+250x−750000=0
⇒ x2+1000x−750x−750000=0
⇒ x(x+1000)−750(x+1000)=0
⇒ (x−750)(x+1000)=0
⇒ x=750 or x=−1000
But speed cannot be negative.
∴ The usual speed is 750 km/hr.