A plane light wave of intensity I=0.20Wcm−2 falls on a plane mirror surface with reflection coefficient ρ=0.8. The angle of incident is 45o. In terms of corpuscular theory, find the magnitude of the normal pressure exerted on that surface:
A
1.2Ncm−2
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B
0.2Ncm−2
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C
2.6Ncm−2
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D
0.53×10−9Nm−2
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Solution
The correct option is D0.53×10−9Nm−2 Considering the incidence at θ=45o angle, the normal Pressure is given by: P=2Icos2(θ)ρc where c is the speed of light. Now, I=0.20Wcm−2 ρ=0.8 c=3×108m/s so the Pressure, P=0.53×10−9Nm−2