Question

A plane makes intercept $1,2,3$ on the co-ordinate axes. If the distance from origin is $p$ then find the value of $p$.

Answer 1

The equation of plane=$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=1=6x+3y+2z=6$

perpendicular distance from origin to plane is = p

formula for distance=$\mid (\frac{0+0+0}{\sqrt{(}{6}^2+3^2+2^2)}-6)\mid =p$

$p=\frac{6}{7}$