A plane mirror and an object approach each other with speeds of 5 m/s and 10 m/s respectively. The speed of the image will be:

5 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 20 m/s
Total speed of the image = Speed of the object + (2 $\times$ Speed of the mirror) = 10 + (2 $\times$ 5) = 10 + 10 = 20 m/s

Suggest Corrections

Similar questions

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be __.

A plane mirror and an object approach each other with speeds of $5 m s^{- 1}$ and $10 m s^{- 1}$ respectively. What will be the speed of the image w.r.t. the stationary observer?

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be 20 $\frac{m}{s e c}$ .

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be

A plane mirror and an object approach each other with speeds of $5 m s^{- 1}$ and $10 m s^{- 1}$ respectively. What will be the speed of the image w.r.t. the stationary observer?

Join BYJU'S Learning Program

A plane mirror and an object approach each other with speeds of 5 m/s and 10 m/s respectively. The speed of the image will be:

The correct option is C 20 m/sTotal speed of the image = Speed of the object + (2 × Speed of the mirror) = 10 + (2 × 5) = 10 + 10 = 20 m/s

The correct option is C 20 m/s
Total speed of the image = Speed of the object + (2 $\times$ Speed of the mirror) = 10 + (2 $\times$ 5) = 10 + 10 = 20 m/s