A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be
The correct option is C. 20 m/s.
Given : Speed of the object = 10 m/sec
Speed of the mirror = 5 m/sec
Mirror and object are approaching each other.
To find:
Speed of image
Let initial position of object be at xoi=0
Let initial position of mirror be at xmi=u
Object distance equals the image distance. Hence, the initial position of the image is xii=2u
Distance is the product of speed and time.
After time t,
Position of object will be:
xof=xoi+uot=5t
Position of mirror will be:
xmf=xmi−uft=u−10t
Let the final position of image be xif.
Using object distance equals image distance after time t,
xif−xmf=xmf−xof
xif=2u−25t
Distance moved by image in time t is:
si=xif−xii
si=−25t
Speed is the ratio of distance and time. Speed of the image is:
vi=sit=−25 m/s
Negative sign appears because image is moving leftwards.
Hence, speed of image is 25 m/s.