A plane mirror is placed at the bottom of a tank containing a liquid of refractive index $π$ . P is a small object at a height h above the mirror. An observer O- vertically above P, outside the liquid sees P and its image in the mirror. The apparent distance between these two will be

2µh

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2h/µ

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Solution

The correct option is B. 2h/µ
The image of P will be formed at a distance h below the mirror.
If d = depth of the liquid in the tank,

Apparent depth of $P = x_{1} = \frac{d - h}{μ}$

Apparent depth of image of $P = x_{2} = \frac{d + h}{μ}$

Apparent distance between P and its image $x_{2} - x_{1} = \frac{2 h}{μ}$ .

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A plane mirror as placed at the bottom of a tank containing a liquid of refractive index, μ. P is a small object at a height h above the mirror. An observer, O vertically above P and outside the liquid P and find its image in a mirror. The apparent distance between these two will be