A plane passes through (2,3, -1) and is perpendicular to the line having direction ratios 3, -4, 7 The perpendicular distance from the origin to this plane is

$\frac{3}{\sqrt{74}}$

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$\frac{5}{\sqrt{74}}$

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$\frac{6}{\sqrt{74}}$

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$\frac{13}{\sqrt{74}}$

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Solution

The correct option is D
$\frac{13}{\sqrt{74}}$

equation to the plane is

$3 x - 4 y + 7 x + 13 = 0$

Distance = $\frac{13}{\sqrt{74}}$

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A plane passes through (2,3, -1) and is perpendicular to the line having direction ratios 3, -4, 7 The perpendicular distance from the origin to this plane is

The correct option is D 13√74 equation to the plane is 3x−4y+7x+13=0 Distance = 13√74

The correct option is D
$\frac{13}{\sqrt{74}}$

equation to the plane is

$3 x - 4 y + 7 x + 13 = 0$

Distance = $\frac{13}{\sqrt{74}}$