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Question

A plane passes through a fixed point (a,b,c). The locus of the foot of the perpendicular to it from the origin is the sphere

A
x2+y2+z2axbycz=0
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B
x2+y2+z22ax2by2cz=0
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C
x2+y2+z24ax4by4cz=0
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D
none of these
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Solution

The correct option is B x2+y2+z2axbycz=0
Let A(a,b,c) be the fixed point on the variable plane.
Now d.r's of OM are x0,y0,z0x,y,z
d.r's of MA are xa,ya,zc.
Since OMMA
Therefore x(xa)+y(yb)+z(zc)=0x2+y2+z2axbycz=0

403999_117108_ans.PNG

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