Question

A plane passes through the points $(2,0,0),(0,3,0)\text{and}(0,0,4)$. The equation of plane is

Answer 1

A plane passes through the points$(2,0,0),(0,3,0)\text{and}(0,0,4)$
So , the intercept of the plane :
$x\text{-intercept}=2$ , $y\text{-intercept}=3$
$z\text{-intercept}=4$
Equation of plane in intercept from is
$\frac{x}{a}+\frac{y}{b}+\frac{z}{4}=1$
$\Rightarrow \frac{x}{2}+\frac{y}{3}+\frac{z}{4}=1$
Hence the equation of plane is
$\frac{x}{2}+\frac{y}{3}+\frac{z}{4}=1$