A plane passing through the line joining the points A(1,−3,5) and B(4,1,−1) is turned about AB till it passes through the origin. The equation of the plane in the new position is
A
3x+4y−6z=0
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B
2x−21y+13z=0
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C
2x−21y−13z=0
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D
none of these
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Solution
The correct option is C2x−21y−13z=0 Equation of plane passing through origin is given by, ax+by+cz=0 Also plane passing through A(1,−3,5) ⇒a−3b+5c=0......(1) It also passes through B(4,1,−1) ⇒4a+b−c=0.....(2) Solving (1) and (2), we get
a=−2c13,b=21c13 Hence, required plane is 2x−21y−13z=0