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Question
A plane polarized monochromatic EM wave is travelling a vacuum along z direction such that at t=t1 it is found that the electric field is zero at a spatial point z1. The next zero that occurs in its neighborhood. is at z2. The frequency of the electromagnetic wave is:
A plane polarized monochromatic EM wave is travelling a vacuum along z direction such that at t=t1 it is found that the electric field is zero at a spatial point z1. The next zero that occurs in its neighborhood. is at z2. The frequency of the electromagnetic wave is:
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Solution
The correct option is A 3×108|z2−z1|
∈=∈o−ei(kz−wt)at t=t1,z=z1,E=o, the next zero that occurs in it's neighborhood is at z2, the frequency of the electromagnetic wave at t2ei(kz1−wt1)=ei(kz2−wt2)kz1−wt1=kz2−wt2(t2−t1)w=k(z−z1) where k=2πλω=2πν
(t2−t1)=2πλ×2πv(z2−z1)
(t2−t1)=1x×v(z2−z1)
λ×v=(z2−z1)(t1−t1)
c=(z2−z1)(t2−t1)
(t2−t1)=(z2−z1)c
Frequency is f∝1t then
1(t2−t1)=c(z2−z1)
frequency =3×108(|z2−z1|)
∈=∈o−ei(kz−wt)
at t=t1,z=z1,E=o,
the next zero that occurs in it's neighborhood is at z2, the frequency of the electromagnetic wave at t2
ei(kz1−wt1)=ei(kz2−wt2)
kz1−wt1=kz2−wt2
(t2−t1)w=k(z−z1)
where k=2πλ
ω=2πν
(t2−t1)=2πλ×2πv(z2−z1)
(t2−t1)=1x×v(z2−z1)
λ×v=(z2−z1)(t1−t1)
c=(z2−z1)(t2−t1)
(t2−t1)=(z2−z1)c
Frequency is f∝1t then
1(t2−t1)=c(z2−z1)
frequency =3×108(|z2−z1|)
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