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Standard XII

Physics

Newton's Law of Gravitation

A planet has ...

Question

A planet has mass 1/10 of that of earth, while radius is 1/3 that of earth. If a person can throw a stone on earth surface to a height of 90 m, then he will be able to trow the stone on that planet to a height-

90 m

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40 m

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300 m

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45 m

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Solution

The correct option is A 300 m
$g$ constant on earth that is $g = \frac{G M}{R}$
$g$ constant on planet that is $g^{1} = \frac{3 G M}{10 R}$
relation between then $g^{1} = \frac{3 g}{10}$
Now energy remains constant
Hence, $m g \times 90 = \frac{m \times 3 g \times h}{100}$
we get $h = 300 m$ .

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A planet has mass $\frac{1}{10}$ of that of earth, while radius is $\frac{1}{3}$ that of earth. If a person can throw a stone on earth surface to a height of 90m, then he will be able to throw the stone on that planet to a height

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A planet has mass 1/10 of that of earth, while radius is 1/3 that of earth. If a person can throw a stone on earth surface to a height of 90 m, then he will be able to trow the stone on that planet to a height-

The correct option is A 300 mg constant on earth that is g=GMRg constant on planet that is g1=3GM10Rrelation between then g1=3g10Now energy remains constantHence, mg×90=m×3g×h100we get h=300m.

The correct option is A 300 m
$g$ constant on earth that is $g = \frac{G M}{R}$
$g$ constant on planet that is $g^{1} = \frac{3 G M}{10 R}$
relation between then $g^{1} = \frac{3 g}{10}$
Now energy remains constant
Hence, $m g \times 90 = \frac{m \times 3 g \times h}{100}$
we get $h = 300 m$ .