A planet has mass and radius both half of earth. Acceleration due to gravity (g) at its surface should be

29.4 m / s^{2}

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19.6 m / s^{2}

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9.8 m / s^{2}

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4.9 m / s^{2}

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Solution

The correct option is D $19.6 m / s^{2}$
Acceleration of gravity of earth, $g = \frac{G M_{e}}{R_{e}^{2}} = 9.81 m s^{- 2}$

Acceleration of gravity on planet, $g^{'} = \frac{G M_{p}}{R_{p}^{2}} = \frac{G (M_{e} / 2)}{{(R_{e} / 2)}^{2}} = 2 g = 19.6 m s^{- 2}$

Hence, acceleration is $19.6 m s^{- 2}$

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A planet has mass and radius both half of earth. Acceleration due to gravity (g) at its surface should be

The correct option is D 19.6m/s2Acceleration of gravity of earth, g=GMeR2e=9.81ms−2 Acceleration of gravity on planet, g′=GMpR2p=G(Me/2)(Re/2)2=2g=19.6ms−2 Hence, acceleration is 19.6ms−2