Question

A planet is revolving around the sun as shown in elliptical path. The correct option is

• A. The time taken in travelling $CDA$ is less than that for $ABC$
  
• B. The time taken in travelling $DAB$ is less than that for $BCD$
• C. The time taken in travelling $CDA$ is greater than that for $ABC$
  
• D. The time taken in travelling $DAB$ is greater than that for $BCD$

Answer 1

The correct option is B The time taken in travelling $DAB$ is less than that for $BCD$

According to Kepler's second law which states, “A radius vector joining any planet to the Sun sweeps out equal areas in equal lengths of time”.

During path $DAB$ planet is nearer to sun as compared with path $BCD$. So, velocity of the planet near point $A$ is higher than at point $C$. So, the time taken in travelling $DAB$ is less than that for $BCD$.
Hence, final answer is (a).