You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Kepler's Law

A planet move...

Question

A planet moves around the sun. At a given point P, it is closest from the sun at a distance $d_{1}$ and has a speed $v_{1}$ . At another point Q, when it is farthest from the sun at a distance $d_{2}$ , its speed will be

$\frac{d_{1}^{2} v_{1}}{d_{2}^{2}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{d_{2} v_{1}}{d_{1}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{d_{1} v_{1}}{d_{2}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{d_{2}^{2} v_{1}}{d_{1}^{2}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$\frac{d_{1} v_{1}}{d_{2}}$

Angular momentum remains constant
$m v_{1} d_{1} = m v_{2} d_{2} \Rightarrow v_{2} = \frac{v_{1} d_{1}}{d_{2}}$

Suggest Corrections

Similar questions

A planet moves around the sun. At a given point P, it is closest from the sun at a distance $d_{1}$ and has a speed $v_{1}$ . At another point Q, when it is farthest from the sun at a distance $d_{2}$ , its speed will be

Q. A planet revolves round the sun. Its velocity at the nearest point, distance

d_{1}

from sun, is

v_{1}

. The velocity of the planet at the farther point distance

d_{2}

from sun will be

Q. A planet is revolving around the sun in an elliptical orbit. Its closest distance from the sun is

r_{m i n}

. The farthest distance from the sun is

r_{m a x}

. If the orbital angular velocity of the planet when it is nearest tothe sun is

ω

, then the orbital angular velocity at the point when it is at the farthest distance from the sun is.

Q. A planet is revolving in an elliptical orbit around the Sun. Its closest distance from the Sun is

r_{m i n}

and the farthest distance is

r_{m a x}

. If the velocity of the planet at the distance of the closest approach is

v_{1}

and that at the farthest distance is

v_{2}

from the Sun, then

\frac{v_{1}}{v_{2}}

Join BYJU'S Learning Program

A planet moves around the sun. At a given point P, it is closest from the sun at a distance d1 and has a speed v1. At another point Q, when it is farthest from the sun at a distance d2, its speed will be

The correct option is C d1v1d2 Angular momentum remains constant mv1d1=mv2d2⇒v2=v1d1d2

A planet moves around the sun. At a given point P, it is closest from the sun at a distance $d_{1}$ and has a speed $v_{1}$ . At another point Q, when it is farthest from the sun at a distance $d_{2}$ , its speed will be

The correct option is C
$\frac{d_{1} v_{1}}{d_{2}}$

Angular momentum remains constant
$m v_{1} d_{1} = m v_{2} d_{2} \Rightarrow v_{2} = \frac{v_{1} d_{1}}{d_{2}}$