A planet of mass m moves around the sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from the sun are r1 and r2 respectively. The time period of the planet is proportional to
A
r2/51
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B
(r1+r2)3/2
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C
(r1−r2)3/2
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D
r3/2
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Solution
The correct option is A(r1+r2)3/2 Kepler's third law:
Square of the time period T is directly proportional to cube of semi-major axis i.e mean distance of the planet r1+r22