Question

A planet revolves around the sun whose mean distance is $1.588$ times the mean distance between earth and sun. The revolution time of planet will be

• A. $1.25$ years
• B. $1.59$ years
• C. $0.89$ years
• D. $2$ years

Answer 1

The correct option is D $2$ years

Given,

$T_{earth}=1year$

$\frac{R_{planet}}{R_{earth}}=1.588$

The Time period and radius relation is given by

$T^2\propto R^3$

$\frac{T_{planet}}{T_{earth}}=(\frac{R_{planet}}{R_{earth}}{)}^{3/2}=(1.588{)}^{3/2}$

$T_{planet}=2T_{earth}$

$T_{planet}=2\times 1=2years$

The correct option is D.