wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

A plank is moving with a velocity 4 m/s. A disc of radius 1 m rolls on it without slipping with an angular velocity of 3 rad/s as shown in figure. Then, the velocity of the centre of the disc (Vcm) is


A
4 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 7 m/s
In pure rolling (rolling without slipping) velocity of contact points (P & Q) will be same.


i.e Velocity of disc at contact point=Velocity of plank
VP=VQ ...(i)
Tangential velocity (ωR) and translational velocity at P are in opposite direction.
VP=VcmωR & VQ=4 m/s
From Eq (i),
VcmωR=4
Vcm=4+(3×1)
Vcm=7 m/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon