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Question

A plank of area of cross section A is half immersed in liquid 1 of density and half in liquid 2 of density 2. What is the period of oscillation of the plank, if it is slightly depressed downwards

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A
T = 2(m/3Ag)
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B
T = 2(m/Ag)
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C
T = 2(2m/3Ag)
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D
T = 2(3m/2Ag)
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Solution

The correct option is B T = 2(m/Ag)

The net buoyancy force acting on the block if it is given a downward displacement x is = 2xAg(xAg)=Agx

Since buoyant force acts as restoring force, we can write ma=Agx or a=(Ag/m)x=w2x

Thus, acceleration is proportional to displacement and the motion is SHM.

The time period of oscillations T=2=2/w=2(m/Ag)


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