A plank with uniform sphere placed on it is being pulled by force F as shown in figure,now choose the appropriate statement,(sphere does not slip on the plank)

Acceleration of centre of sphere is less than that of plank

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Acceleration of centre of sphere is more than that of plank

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Total work done by force is equal to change in kinetic energy.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A Acceleration of centre of sphere is less than that of plank
C Total work done by force is equal to change in kinetic energy.
$a_{p} = \frac{F - f}{m_{p}} a_{s} = \frac{F}{m_{s}} a l s o a_{s} = \frac{5 f_{r}}{2 m_{s} r^{2}}$

$a_{s} + r a_{s} = a_{p}$ (condition for no slipping)

$\frac{τ}{2} a_{s} = a_{p}$

so $, a_{s} < a_{p}$
Hence we see here that acceeration of center of sphere is less than that of plank.
By work energy theorem (as there is no slipping),

$W = Δ K E$

Hence the total work done by the force is equal to change in kinetic energy.

Suggest Corrections

Similar questions

F

F

F_{1}

2 R

R / 2

F_{2}

F_{1} / F_{2}

Join BYJU'S Learning Program