A plate load test is conducted on a cohesionless soil with a test plate having width $B_{p} (c m)$ and settlement of this plate $S_{p} (c m)$ is obtained at the same load intensity as a foundation. A footing having a width $B_{f} (c m)$ is to be constructed as foundation. What is the settlement $S_{f} (c m)$ experienced by this footing?

S_{f} = S_{p} {[B_{f} (B_{P} + 30)] / [B_{p} (B_{f} + 30)]}^{2}

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S_{f} = S_{p} {[B_{p} (B_{f} + 30)] / [B_{f} (B_{p} + 30)]}^{2}

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S_{f} = S_{p} [B_{f} / B_{p}]

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S_{f} = S_{p} [B_{p} / B_{f}]

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Solution

The correct option is A $S_{f} = S_{p} {[B_{f} (B_{P} + 30)] / [B_{p} (B_{f} + 30)]}^{2}$
The size effect of footing has been considered by empirically evolving the equation:

$\frac{S_{f}}{S_{p}} = {(\frac{B_{f} (B_{P} + 30)}{B_{P} (B_{f} + 30)})}^{2}$

This equation is applicable for dense sands having general shear failure.

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