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Question

A plate of mass M is held in air by firing bullets each of mass m with same velocity in vertically upward direction. If n bullets are fired per minute and each bullet strikes the plate with speed v and rebounds with half the speed with which it strikes the plate, then the speed with which bullets are striking the plate is [Take g = 10m/s^2]

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Solution

Dear Student,
Answer to your question is given below:

Given mass of bullet = m and mass of Plate = M Now change in momentum of bullet will give the impulse imparted to plate, Initial Velocity of bullet = v in m/s Final velocity of bullet = -v2 m/s Change in momentum of bullet = mv - (-mv2) dP = 3mv2Now change in momentum, Fdt = dP F = n60×3mv2and F should balance the weight of Plate Mg = n60×3mv2 v = 40MgnmTherfore the speed with which bullets are striking the plate is 40Mgnm
Regards,


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