A platinum resistance thermometer reads 0o when its resistance is 80- and 100o when its resistance is 90- Find the temperature at the platinum scale at which the resistance is 86-

R_t = 86Ω; R_0^o = 80Ω; R_100^o = 90Ω t = R_t R_0R_100 R_0× 100 = 86 8090 80× 100=60^oC ...

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Standard XII

Physics

Scale Conversions

A platinum re...

Question

A platinum resistance thermometer reads $0^{o}$ when its resistance is $80 Ω$ and $100^{o}$ when its resistance is $90 Ω$ . Find the temperature at the platinum scale at which the resistance is $86 Ω$ .

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Solution

$R_{t} = 86 Ω; R_{0^{o}} = 80 Ω; R_{100^{o}} = 90 Ω$

$t = \frac{R_{t} - R_{0}}{R_{100} - R_{0}} \times 100 = \frac{86 - 80}{90 - 80} \times 100 = 60^{o} C$

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A platinum resistance thermometer reads 0o when its resistance is 80Ω and 100o when its resistance is 90Ω. Find the temperature at the platinum scale at which the resistance is 86Ω.

Rt=86Ω;R0o=80Ω;R100o=90Ωt=Rt−R0R100−R0×100=86−8090−80×100=60oC

A platinum resistance thermometer reads $0^{o}$ when its resistance is $80 Ω$ and $100^{o}$ when its resistance is $90 Ω$ . Find the temperature at the platinum scale at which the resistance is $86 Ω$ .

$R_{t} = 86 Ω; R_{0^{o}} = 80 Ω; R_{100^{o}} = 90 Ω$

$t = \frac{R_{t} - R_{0}}{R_{100} - R_{0}} \times 100 = \frac{86 - 80}{90 - 80} \times 100 = 60^{o} C$